What are the solutions to the equation c^2+3c+5=0 ?

The solutions to the equation c^2+3c+5=0 are c=-3/2+i(sqrt(11))/2 ,c=-3/2-i(sqrt(11))/2

Find the zeros of c^2+3c+5=0

The zeros of c^2+3c+5=0 are c=-3/2+i(sqrt(11))/2 ,c=-3/2-i(sqrt(11))/2

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c^{2} + 3 c + 5 = 0

c = - \frac{3}{2} + i \frac{11}{2}, c = - \frac{3}{2} - i \frac{11}{2}

Solution steps

c^{2} + 3 c + 5 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 5 : 11 i

c_{1, 2} = \frac{- 3 \pm 11 i}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 3 + 11 i}{2 \cdot 1}, c_{2} = \frac{- 3 - 11 i}{2 \cdot 1}

c = \frac{- 3 + 11 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{11}{2}

c = \frac{- 3 - 11 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

c = - \frac{3}{2} + i \frac{11}{2}, c = - \frac{3}{2} - i \frac{11}{2}

x^{2} - 6 = - 7 x

(3 x - 2)^{2} + 8 (3 x - 2) + 12 = 0

r^{2} + r + 0 = 0

x^{2} + 6 x - 247 = 0

5 u^{2} - 15 u = 0

What are the solutions to the equation c^2+3c+5=0 ?
The solutions to the equation c^2+3c+5=0 are c=-3/2+i(sqrt(11))/2 ,c=-3/2-i(sqrt(11))/2
Find the zeros of c^2+3c+5=0
The zeros of c^2+3c+5=0 are c=-3/2+i(sqrt(11))/2 ,c=-3/2-i(sqrt(11))/2