What are the solutions to the equation 3x^2-5x=28 ?

The solutions to the equation 3x^2-5x=28 are x=4,x=-7/3

Find the zeros of 3x^2-5x=28

The zeros of 3x^2-5x=28 are x=4,x=-7/3

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3 x^{2} - 5 x = 28

x = 4, x = - \frac{7}{3}

Decimal Notation

x = 4, x = - 2.33333 \dots

Solution steps

3 x^{2} - 5 x = 28

Move

28

to the left side

3 x^{2} - 5 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 28 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 28) = 19

x_{1, 2} = \frac{- ( - 5 ) \pm 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 19}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 19}{2 \cdot 3}

x = \frac{- ( - 5 ) + 19}{2 \cdot 3} : 4

x = \frac{- ( - 5 ) - 19}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{7}{3}

2 x^{2} + 32 x + 144 = 0

- \frac{2}{3} x^{2} - 4 x - 3 = - \frac{1}{6} x^{2} - x - 3

132 x - 12 x^{2} = 0

x, x^{2} + y^{2} - 4 x + 2 y + 36 = 0

b, b^{2} + d^{2} = 14 b d

What are the solutions to the equation 3x^2-5x=28 ?
The solutions to the equation 3x^2-5x=28 are x=4,x=-7/3
Find the zeros of 3x^2-5x=28
The zeros of 3x^2-5x=28 are x=4,x=-7/3