What are the solutions to the equation (2-x)(3-x)-6=0 ?

The solutions to the equation (2-x)(3-x)-6=0 are x=5,x=0

Find the zeros of (2-x)(3-x)-6=0

The zeros of (2-x)(3-x)-6=0 are x=5,x=0

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(2 - x) (3 - x) - 6 = 0

x = 5, x = 0

Solution steps

(2 - x) (3 - x) - 6 = 0

Expand

(2 - x) (3 - x) - 6 : x^{2} - 5 x

x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

x = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 5, x = 0

2 x^{2} + 3 x + 1 = 0

- 9 x^{2} - 11 = - 10 x

- 4.9 t^{2} - 5 t + 450 = 0

4 y^{2} + 20 y = - 36

x, x^{2} - 2 x y - y^{2} = 0

What are the solutions to the equation (2-x)(3-x)-6=0 ?
The solutions to the equation (2-x)(3-x)-6=0 are x=5,x=0
Find the zeros of (2-x)(3-x)-6=0
The zeros of (2-x)(3-x)-6=0 are x=5,x=0