What are the solutions to the equation 4y^2+20y=-36 ?

The solutions to the equation 4y^2+20y=-36 are y=-5/2+i(sqrt(11))/2 ,y=-5/2-i(sqrt(11))/2

Find the zeros of 4y^2+20y=-36

The zeros of 4y^2+20y=-36 are y=-5/2+i(sqrt(11))/2 ,y=-5/2-i(sqrt(11))/2

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4 y^{2} + 20 y = - 36

y = - \frac{5}{2} + i \frac{11}{2}, y = - \frac{5}{2} - i \frac{11}{2}

Solution steps

4 y^{2} + 20 y = - 36

Move

36

to the left side

4 y^{2} + 20 y + 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 36}{2 \cdot 4}

Simplify

2 0^{2} - 4 \cdot 4 \cdot 36 : 411 i

y_{1, 2} = \frac{- 20 \pm 4 11 i}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- 20 + 4 11 i}{2 \cdot 4}, y_{2} = \frac{- 20 - 4 11 i}{2 \cdot 4}

y = \frac{- 20 + 4 11 i}{2 \cdot 4} : - \frac{5}{2} + i \frac{11}{2}

y = \frac{- 20 - 4 11 i}{2 \cdot 4} : - \frac{5}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

y = - \frac{5}{2} + i \frac{11}{2}, y = - \frac{5}{2} - i \frac{11}{2}

x, x^{2} - 2 x y - y^{2} = 0

24 x^{2} + 96 x + 72 = 0

(100 x - 0.5 x^{2}) - (60 x + 300) = 300

y, x = (y - 2)^{2}

- 6 x^{2} + 4 x = 0

What are the solutions to the equation 4y^2+20y=-36 ?
The solutions to the equation 4y^2+20y=-36 are y=-5/2+i(sqrt(11))/2 ,y=-5/2-i(sqrt(11))/2
Find the zeros of 4y^2+20y=-36
The zeros of 4y^2+20y=-36 are y=-5/2+i(sqrt(11))/2 ,y=-5/2-i(sqrt(11))/2