What are the solutions to the equation -9x^2-11=-10x ?

The solutions to the equation -9x^2-11=-10x are x= 5/9-i(sqrt(74))/9 ,x= 5/9+i(sqrt(74))/9

Find the zeros of -9x^2-11=-10x

The zeros of -9x^2-11=-10x are x= 5/9-i(sqrt(74))/9 ,x= 5/9+i(sqrt(74))/9

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- 9 x^{2} - 11 = - 10 x

x = \frac{5}{9} - i \frac{74}{9}, x = \frac{5}{9} + i \frac{74}{9}

Solution steps

- 9 x^{2} - 11 = - 10 x

Move

10 x

to the left side

- 9 x^{2} - 11 + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 9 x^{2} + 10 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 9 ) ( - 11 )}{2 ( - 9 )}

Simplify

1 0^{2} - 4 (- 9) (- 11) : 274 i

x_{1, 2} = \frac{- 10 \pm 2 74 i}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 74 i}{2 ( - 9 )}, x_{2} = \frac{- 10 - 2 74 i}{2 ( - 9 )}

x = \frac{- 10 + 2 74 i}{2 ( - 9 )} : \frac{5}{9} - i \frac{74}{9}

x = \frac{- 10 - 2 74 i}{2 ( - 9 )} : \frac{5}{9} + i \frac{74}{9}

The solutions to the quadratic equation are:

x = \frac{5}{9} - i \frac{74}{9}, x = \frac{5}{9} + i \frac{74}{9}

- 4.9 t^{2} - 5 t + 450 = 0

4 y^{2} + 20 y = - 36

x, x^{2} - 2 x y - y^{2} = 0

24 x^{2} + 96 x + 72 = 0

(100 x - 0.5 x^{2}) - (60 x + 300) = 300

What are the solutions to the equation -9x^2-11=-10x ?
The solutions to the equation -9x^2-11=-10x are x= 5/9-i(sqrt(74))/9 ,x= 5/9+i(sqrt(74))/9
Find the zeros of -9x^2-11=-10x
The zeros of -9x^2-11=-10x are x= 5/9-i(sqrt(74))/9 ,x= 5/9+i(sqrt(74))/9