What are the solutions to the equation 24x^2+96x+72=0 ?

The solutions to the equation 24x^2+96x+72=0 are x=-1,x=-3

Find the zeros of 24x^2+96x+72=0

The zeros of 24x^2+96x+72=0 are x=-1,x=-3

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24 x^{2} + 96 x + 72 = 0

x = - 1, x = - 3

Solution steps

24 x^{2} + 96 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 \cdot 24 \cdot 72}{2 \cdot 24}

9 6^{2} - 4 \cdot 24 \cdot 72 = 48

x_{1, 2} = \frac{- 96 \pm 48}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- 96 + 48}{2 \cdot 24}, x_{2} = \frac{- 96 - 48}{2 \cdot 24}

x = \frac{- 96 + 48}{2 \cdot 24} : - 1

x = \frac{- 96 - 48}{2 \cdot 24} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

(100 x - 0.5 x^{2}) - (60 x + 300) = 300

y, x = (y - 2)^{2}

- 6 x^{2} + 4 x = 0

15 t^{2} - t - 6 = 1, 5 t^{2} - t - 6 = 0

x^{2} - 8 x - 22 = 6

What are the solutions to the equation 24x^2+96x+72=0 ?
The solutions to the equation 24x^2+96x+72=0 are x=-1,x=-3
Find the zeros of 24x^2+96x+72=0
The zeros of 24x^2+96x+72=0 are x=-1,x=-3