What are the solutions to the equation 9-y-3y^2=7 ?

The solutions to the equation 9-y-3y^2=7 are y=-1,y= 2/3

Find the zeros of 9-y-3y^2=7

The zeros of 9-y-3y^2=7 are y=-1,y= 2/3

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9 - y - 3 y^{2} = 7

y = - 1, y = \frac{2}{3}

Decimal Notation

y = - 1, y = 0.66666 \dots

Solution steps

9 - y - 3 y^{2} = 7

Move

7

to the left side

- 3 y^{2} - y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

(- 1)^{2} - 4 (- 3) \cdot 2 = 5

y_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 3 )}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 5}{2 ( - 3 )}, y_{2} = \frac{- ( - 1 ) - 5}{2 ( - 3 )}

y = \frac{- ( - 1 ) + 5}{2 ( - 3 )} : - 1

y = \frac{- ( - 1 ) - 5}{2 ( - 3 )} : \frac{2}{3}

The solutions to the quadratic equation are:

y = - 1, y = \frac{2}{3}

3 k^{2} + 5 k + 2 = 0

3 x^{2} + 5 x + 1 = 2 + x

b^{2} x^{2} + 2 b x a = 3 a^{2}

2 x (10 x + 8) = - 3 (x + 1)

- x^{2} + 8 = 0

What are the solutions to the equation 9-y-3y^2=7 ?
The solutions to the equation 9-y-3y^2=7 are y=-1,y= 2/3
Find the zeros of 9-y-3y^2=7
The zeros of 9-y-3y^2=7 are y=-1,y= 2/3