What are the solutions to the equation 32=-16t^2+16t+32 ?

The solutions to the equation 32=-16t^2+16t+32 are t=0,t=1

Find the zeros of 32=-16t^2+16t+32

The zeros of 32=-16t^2+16t+32 are t=0,t=1

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32 = - 16 t^{2} + 16 t + 32

t = 0, t = 1

Solution steps

32 = - 16 t^{2} + 16 t + 32

Switch sides

- 16 t^{2} + 16 t + 32 = 32

Move

32

to the left side

- 16 t^{2} + 16 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 0 = 16

t_{1, 2} = \frac{- 16 \pm 16}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 16 + 16}{2 ( - 16 )}, t_{2} = \frac{- 16 - 16}{2 ( - 16 )}

t = \frac{- 16 + 16}{2 ( - 16 )} : 0

t = \frac{- 16 - 16}{2 ( - 16 )} : 1

The solutions to the quadratic equation are:

t = 0, t = 1

s^{2} = 2

x^{2} + 16 x = - 8

u^{2} + 4 u - 5 = 0

x, 12 x^{2} - 12 = 0

6 x + 55 = x^{2}

What are the solutions to the equation 32=-16t^2+16t+32 ?
The solutions to the equation 32=-16t^2+16t+32 are t=0,t=1
Find the zeros of 32=-16t^2+16t+32
The zeros of 32=-16t^2+16t+32 are t=0,t=1