What are the solutions to the equation u^2+4u-5=0 ?

The solutions to the equation u^2+4u-5=0 are u=1,u=-5

Find the zeros of u^2+4u-5=0

The zeros of u^2+4u-5=0 are u=1,u=-5

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u^{2} + 4 u - 5 = 0

u = 1, u = - 5

Solution steps

u^{2} + 4 u - 5 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

u_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 4 + 6}{2 \cdot 1}, u_{2} = \frac{- 4 - 6}{2 \cdot 1}

u = \frac{- 4 + 6}{2 \cdot 1} : 1

u = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

u = 1, u = - 5

x, 12 x^{2} - 12 = 0

6 x + 55 = x^{2}

3 x^{2} - 60 x + 296 = 0

(x - 5)^{2} - 7 = 8

y^{2} - 4 y + 12 + 4 = 0

What are the solutions to the equation u^2+4u-5=0 ?
The solutions to the equation u^2+4u-5=0 are u=1,u=-5
Find the zeros of u^2+4u-5=0
The zeros of u^2+4u-5=0 are u=1,u=-5