What are the solutions to the equation x^2+16x=-8 ?

The solutions to the equation x^2+16x=-8 are x=2(sqrt(14)-4),x=-2(4+sqrt(14))

Find the zeros of x^2+16x=-8

The zeros of x^2+16x=-8 are x=2(sqrt(14)-4),x=-2(4+sqrt(14))

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x^{2} + 16 x = - 8

x = 2 (14 - 4), x = - 2 (4 + 14)

Decimal Notation

x = - 0.51668 \dots, x = - 15.48331 \dots

Solution steps

x^{2} + 16 x = - 8

Move

8

to the left side

x^{2} + 16 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 8 = 414

x_{1, 2} = \frac{- 16 \pm 4 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4 14}{2 \cdot 1}, x_{2} = \frac{- 16 - 4 14}{2 \cdot 1}

x = \frac{- 16 + 4 14}{2 \cdot 1} : 2 (14 - 4)

x = \frac{- 16 - 4 14}{2 \cdot 1} : - 2 (4 + 14)

The solutions to the quadratic equation are:

x = 2 (14 - 4), x = - 2 (4 + 14)

u^{2} + 4 u - 5 = 0

x, 12 x^{2} - 12 = 0

6 x + 55 = x^{2}

3 x^{2} - 60 x + 296 = 0

(x - 5)^{2} - 7 = 8

What are the solutions to the equation x^2+16x=-8 ?
The solutions to the equation x^2+16x=-8 are x=2(sqrt(14)-4),x=-2(4+sqrt(14))
Find the zeros of x^2+16x=-8
The zeros of x^2+16x=-8 are x=2(sqrt(14)-4),x=-2(4+sqrt(14))