What are the solutions to the equation x^2+8x-64=0 ?

The solutions to the equation x^2+8x-64=0 are x=4(sqrt(5)-1),x=-4(1+sqrt(5))

Find the zeros of x^2+8x-64=0

The zeros of x^2+8x-64=0 are x=4(sqrt(5)-1),x=-4(1+sqrt(5))

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x^{2} + 8 x - 64 = 0

x = 4 (5 - 1), x = - 4 (1 + 5)

Decimal Notation

x = 4.94427 \dots, x = - 12.94427 \dots

Solution steps

x^{2} + 8 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 64) = 85

x_{1, 2} = \frac{- 8 \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 5}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 5}{2 \cdot 1}

x = \frac{- 8 + 8 5}{2 \cdot 1} : 4 (5 - 1)

x = \frac{- 8 - 8 5}{2 \cdot 1} : - 4 (1 + 5)

The solutions to the quadratic equation are:

x = 4 (5 - 1), x = - 4 (1 + 5)

3 (x + 1)^{2} - 48 = 0

X, Y = X^{2} - 4 X + 3

- 7 x^{2} + 7 x + 140 = 0

x, x^{2} + y^{2} - 2 y - z + 1 = 0

x, x^{2} + 4 x + 8 = 0

What are the solutions to the equation x^2+8x-64=0 ?
The solutions to the equation x^2+8x-64=0 are x=4(sqrt(5)-1),x=-4(1+sqrt(5))
Find the zeros of x^2+8x-64=0
The zeros of x^2+8x-64=0 are x=4(sqrt(5)-1),x=-4(1+sqrt(5))