What are the solutions to the equation c^2-8c=0 ?

The solutions to the equation c^2-8c=0 are c=8,c=0

Find the zeros of c^2-8c=0

The zeros of c^2-8c=0 are c=8,c=0

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c^{2} - 8 c = 0

c = 8, c = 0

Solution steps

c^{2} - 8 c = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

c_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, c_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

c = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

c = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

c = 8, c = 0

r^{2} + 5 r = 0

s^{2} + 4 s - 60 = 0

4 x^{2} - 31 x - 45 = 0

x^{2} + 11 x = - 35

y = 0.00249 (1 - \frac{1.197 - 1100 y}{- 2})^{2}

What are the solutions to the equation c^2-8c=0 ?
The solutions to the equation c^2-8c=0 are c=8,c=0
Find the zeros of c^2-8c=0
The zeros of c^2-8c=0 are c=8,c=0