What are the solutions to the equation x^2-16x-612=0 ?

The solutions to the equation x^2-16x-612=0 are x=34,x=-18

Find the zeros of x^2-16x-612=0

The zeros of x^2-16x-612=0 are x=34,x=-18

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x^{2} - 16 x - 612 = 0

x = 34, x = - 18

Solution steps

x^{2} - 16 x - 612 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 612 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 612) = 52

x_{1, 2} = \frac{- ( - 16 ) \pm 52}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 52}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 52}{2 \cdot 1}

x = \frac{- ( - 16 ) + 52}{2 \cdot 1} : 34

x = \frac{- ( - 16 ) - 52}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 34, x = - 18

x^{2} + 6 x - 4 = x + 2

p^{2} + 4 p + 6 = 0

x, x^{2} + \frac{k}{m} x = 0

r, x^{2} r^{2} - 3 x r + 3 = 0

0 = 255 - 21 t - 16 t^{2}

What are the solutions to the equation x^2-16x-612=0 ?
The solutions to the equation x^2-16x-612=0 are x=34,x=-18
Find the zeros of x^2-16x-612=0
The zeros of x^2-16x-612=0 are x=34,x=-18