What are the solutions to the equation x^2+4-2x=0 ?

The solutions to the equation x^2+4-2x=0 are x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of x^2+4-2x=0

The zeros of x^2+4-2x=0 are x=1+sqrt(3)i,x=1-sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 - 2 x = 0

x = 1 + 3 i, x = 1 - 3 i

Solution steps

x^{2} + 4 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1} : 1 + 3 i

x = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

x^{2} + x - 6 = 6

a, x^{2} + (y - a)^{2} = 25

x, x^{2} - 4 x = - 4

n^{2} + 4 n = 32

12 x^{2} - 12 x - 2 = 0

What are the solutions to the equation x^2+4-2x=0 ?
The solutions to the equation x^2+4-2x=0 are x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of x^2+4-2x=0
The zeros of x^2+4-2x=0 are x=1+sqrt(3)i,x=1-sqrt(3)i