What are the solutions to the equation -3p^2+6p-2=0 ?

The solutions to the equation -3p^2+6p-2=0 are p=(3-sqrt(3))/3 ,p=(3+sqrt(3))/3

Find the zeros of -3p^2+6p-2=0

The zeros of -3p^2+6p-2=0 are p=(3-sqrt(3))/3 ,p=(3+sqrt(3))/3

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- 3 p^{2} + 6 p - 2 = 0

p = \frac{3 - 3}{3}, p = \frac{3 + 3}{3}

Decimal Notation

p = 0.42264 \dots, p = 1.57735 \dots

Solution steps

- 3 p^{2} + 6 p - 2 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

6^{2} - 4 (- 3) (- 2) = 23

p_{1, 2} = \frac{- 6 \pm 2 3}{2 ( - 3 )}

Separate the solutions

p_{1} = \frac{- 6 + 2 3}{2 ( - 3 )}, p_{2} = \frac{- 6 - 2 3}{2 ( - 3 )}

p = \frac{- 6 + 2 3}{2 ( - 3 )} : \frac{3 - 3}{3}

p = \frac{- 6 - 2 3}{2 ( - 3 )} : \frac{3 + 3}{3}

The solutions to the quadratic equation are:

p = \frac{3 - 3}{3}, p = \frac{3 + 3}{3}

2 x^{2} - x + 16 = x

(x - 2)^{2} - 4 x + 8 = 0

f^{2} - 4 f = 21

6 x^{2} - 2 = 7 x

2 x^{2} - 16 x + 16 = - 10 + 16

What are the solutions to the equation -3p^2+6p-2=0 ?
The solutions to the equation -3p^2+6p-2=0 are p=(3-sqrt(3))/3 ,p=(3+sqrt(3))/3
Find the zeros of -3p^2+6p-2=0
The zeros of -3p^2+6p-2=0 are p=(3-sqrt(3))/3 ,p=(3+sqrt(3))/3