What are the solutions to the equation (1-(-1))x^2-(-1+1)x-2=0 ?

The solutions to the equation (1-(-1))x^2-(-1+1)x-2=0 are x=1,x=-1

Find the zeros of (1-(-1))x^2-(-1+1)x-2=0

The zeros of (1-(-1))x^2-(-1+1)x-2=0 are x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1 - (- 1)) x^{2} - (- 1 + 1) x - 2 = 0

x = 1, x = - 1

Solution steps

(1 - (- 1)) x^{2} - (- 1 + 1) x - 2 = 0

Expand

(1 - (- 1)) x^{2} - (- 1 + 1) x - 2 : 2 x^{2} - 2

2 x^{2} - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 2) = 4

x_{1, 2} = \frac{- 0 \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 4}{2 \cdot 2}, x_{2} = \frac{- 0 - 4}{2 \cdot 2}

x = \frac{- 0 + 4}{2 \cdot 2} : 1

x = \frac{- 0 - 4}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 1, x = - 1

x^{2} + 16 x - 1 = 0

(n - 5)^{2} - 30 = 70

9 t^{2} - 9 t - 4 = 0

n^{2} = 10 + 3 n

2 x - \frac{1}{2} x^{2} = 0

What are the solutions to the equation (1-(-1))x^2-(-1+1)x-2=0 ?
The solutions to the equation (1-(-1))x^2-(-1+1)x-2=0 are x=1,x=-1
Find the zeros of (1-(-1))x^2-(-1+1)x-2=0
The zeros of (1-(-1))x^2-(-1+1)x-2=0 are x=1,x=-1