What are the solutions to the equation 9t^2-9t-4=0 ?

The solutions to the equation 9t^2-9t-4=0 are t= 4/3 ,t=-1/3

Find the zeros of 9t^2-9t-4=0

The zeros of 9t^2-9t-4=0 are t= 4/3 ,t=-1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 t^{2} - 9 t - 4 = 0

t = \frac{4}{3}, t = - \frac{1}{3}

Decimal Notation

t = 1.33333 \dots, t = - 0.33333 \dots

Solution steps

9 t^{2} - 9 t - 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

(- 9)^{2} - 4 \cdot 9 (- 4) = 15

t_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 9}

Separate the solutions

t_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 9}, t_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 9}

t = \frac{- ( - 9 ) + 15}{2 \cdot 9} : \frac{4}{3}

t = \frac{- ( - 9 ) - 15}{2 \cdot 9} : - \frac{1}{3}

The solutions to the quadratic equation are:

t = \frac{4}{3}, t = - \frac{1}{3}

n^{2} = 10 + 3 n

2 x - \frac{1}{2} x^{2} = 0

- 8 x^{2} - 12 (- 2) + C = 0

4 x^{2} - 6 x + 8 = 0

w^{2} - 2 w + 5 = 0

What are the solutions to the equation 9t^2-9t-4=0 ?
The solutions to the equation 9t^2-9t-4=0 are t= 4/3 ,t=-1/3
Find the zeros of 9t^2-9t-4=0
The zeros of 9t^2-9t-4=0 are t= 4/3 ,t=-1/3