What are the solutions to the equation 7x^2-23x+6=0 ?

The solutions to the equation 7x^2-23x+6=0 are x=3,x= 2/7

Find the zeros of 7x^2-23x+6=0

The zeros of 7x^2-23x+6=0 are x=3,x= 2/7

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7 x^{2} - 23 x + 6 = 0

x = 3, x = \frac{2}{7}

Decimal Notation

x = 3, x = 0.28571 \dots

Solution steps

7 x^{2} - 23 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 7 \cdot 6}{2 \cdot 7}

(- 23)^{2} - 4 \cdot 7 \cdot 6 = 19

x_{1, 2} = \frac{- ( - 23 ) \pm 19}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 19}{2 \cdot 7}, x_{2} = \frac{- ( - 23 ) - 19}{2 \cdot 7}

x = \frac{- ( - 23 ) + 19}{2 \cdot 7} : 3

x = \frac{- ( - 23 ) - 19}{2 \cdot 7} : \frac{2}{7}

The solutions to the quadratic equation are:

x = 3, x = \frac{2}{7}

12 x^{2} - 11 x + 2 = 0

10 r^{2} - 2 r - 18 = 0

m^{2} - 8 m + 9 = 0

x, 4 x^{2} - 3 k x + 10 = 0

x (x + 2) = 80

What are the solutions to the equation 7x^2-23x+6=0 ?
The solutions to the equation 7x^2-23x+6=0 are x=3,x= 2/7
Find the zeros of 7x^2-23x+6=0
The zeros of 7x^2-23x+6=0 are x=3,x= 2/7