What are the solutions to the equation 10r^2-2r-18=0 ?

The solutions to the equation 10r^2-2r-18=0 are r=(1+sqrt(181))/(10),r=(1-sqrt(181))/(10)

Find the zeros of 10r^2-2r-18=0

The zeros of 10r^2-2r-18=0 are r=(1+sqrt(181))/(10),r=(1-sqrt(181))/(10)

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10 r^{2} - 2 r - 18 = 0

r = \frac{1 + 181}{10}, r = \frac{1 - 181}{10}

Decimal Notation

r = 1.44536 \dots, r = - 1.24536 \dots

Solution steps

10 r^{2} - 2 r - 18 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 ( - 18 )}{2 \cdot 10}

(- 2)^{2} - 4 \cdot 10 (- 18) = 2181

r_{1, 2} = \frac{- ( - 2 ) \pm 2 181}{2 \cdot 10}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 2 181}{2 \cdot 10}, r_{2} = \frac{- ( - 2 ) - 2 181}{2 \cdot 10}

r = \frac{- ( - 2 ) + 2 181}{2 \cdot 10} : \frac{1 + 181}{10}

r = \frac{- ( - 2 ) - 2 181}{2 \cdot 10} : \frac{1 - 181}{10}

The solutions to the quadratic equation are:

r = \frac{1 + 181}{10}, r = \frac{1 - 181}{10}

m^{2} - 8 m + 9 = 0

x, 4 x^{2} - 3 k x + 10 = 0

x (x + 2) = 80

t^{2} - 9 t = 0

x, 16 x^{2} + 24 x y + 9 y^{2} - 15 x + 20 y - 25 = 0

What are the solutions to the equation 10r^2-2r-18=0 ?
The solutions to the equation 10r^2-2r-18=0 are r=(1+sqrt(181))/(10),r=(1-sqrt(181))/(10)
Find the zeros of 10r^2-2r-18=0
The zeros of 10r^2-2r-18=0 are r=(1+sqrt(181))/(10),r=(1-sqrt(181))/(10)