What are the solutions to the equation 2x^2+1=17 ?

The solutions to the equation 2x^2+1=17 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of 2x^2+1=17

The zeros of 2x^2+1=17 are x=2sqrt(2),x=-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 1 = 17

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

2 x^{2} + 1 = 17

Move

1

to the right side

2 x^{2} = 16

Divide both sides by

2

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

2 x^{2} + 1 = 19

x^{2} - 6 x = 0

2 x^{2} + 1 = 8 x

5 x^{2} - 9 = 11 x

x, 3 x^{2} + 2 x + 2 = k x + k

What are the solutions to the equation 2x^2+1=17 ?
The solutions to the equation 2x^2+1=17 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of 2x^2+1=17
The zeros of 2x^2+1=17 are x=2sqrt(2),x=-2sqrt(2)