What are the solutions to the equation x^2+x/4+1/8 =0 ?

The solutions to the equation x^2+x/4+1/8 =0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8

Find the zeros of x^2+x/4+1/8 =0

The zeros of x^2+x/4+1/8 =0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8

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x^{2} + \frac{x}{4} + \frac{1}{8} = 0

x = - \frac{1}{8} + i \frac{7}{8}, x = - \frac{1}{8} - i \frac{7}{8}

Solution steps

x^{2} + \frac{x}{4} + \frac{1}{8} = 0

Find Least Common Multiplier of

4, 8 : 8

Multiply by LCM=

8

x^{2} \cdot 8 + \frac{x}{4} \cdot 8 + \frac{1}{8} \cdot 8 = 0 \cdot 8

Simplify

8 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

Simplify

2^{2} - 4 \cdot 8 \cdot 1 : 27 i

x_{1, 2} = \frac{- 2 \pm 2 7 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 2 + 2 7 i}{2 \cdot 8}, x_{2} = \frac{- 2 - 2 7 i}{2 \cdot 8}

x = \frac{- 2 + 2 7 i}{2 \cdot 8} : - \frac{1}{8} + i \frac{7}{8}

x = \frac{- 2 - 2 7 i}{2 \cdot 8} : - \frac{1}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = - \frac{1}{8} + i \frac{7}{8}, x = - \frac{1}{8} - i \frac{7}{8}

x^{2} + 4 x + 5 = 0

5 x^{2} + 16 x = - 3

x^{2} + 16 x - 11 = 4

2 x^{2} - 196 x - 960 = 0

s^{2} + 1.2 s + 0.2924

What are the solutions to the equation x^2+x/4+1/8 =0 ?
The solutions to the equation x^2+x/4+1/8 =0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8
Find the zeros of x^2+x/4+1/8 =0
The zeros of x^2+x/4+1/8 =0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8