What are the solutions to the equation 5x^2+16x=-3 ?

The solutions to the equation 5x^2+16x=-3 are x=-1/5 ,x=-3

Find the zeros of 5x^2+16x=-3

The zeros of 5x^2+16x=-3 are x=-1/5 ,x=-3

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5 x^{2} + 16 x = - 3

x = - \frac{1}{5}, x = - 3

Decimal

x = - 0.2, x = - 3

Solution steps

5 x^{2} + 16 x = - 3

Move

3

to the left side

5 x^{2} + 16 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

1 6^{2} - 4 \cdot 5 \cdot 3 = 14

x_{1, 2} = \frac{- 16 \pm 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 16 + 14}{2 \cdot 5}, x_{2} = \frac{- 16 - 14}{2 \cdot 5}

x = \frac{- 16 + 14}{2 \cdot 5} : - \frac{1}{5}

x = \frac{- 16 - 14}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - 3

x^{2} + 16 x - 11 = 4

2 x^{2} - 196 x - 960 = 0

s^{2} + 1.2 s + 0.2924

5 z^{2} + 8 z + 5 = 0

x^{2} - 7 x + 27 = 15

What are the solutions to the equation 5x^2+16x=-3 ?
The solutions to the equation 5x^2+16x=-3 are x=-1/5 ,x=-3
Find the zeros of 5x^2+16x=-3
The zeros of 5x^2+16x=-3 are x=-1/5 ,x=-3