What are the solutions to the equation x^2+16x-11=4 ?

The solutions to the equation x^2+16x-11=4 are x=-8+sqrt(79),x=-8-sqrt(79)

Find the zeros of x^2+16x-11=4

The zeros of x^2+16x-11=4 are x=-8+sqrt(79),x=-8-sqrt(79)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 16 x - 11 = 4

x = - 8 + 79, x = - 8 - 79

Decimal Notation

x = 0.88819 \dots, x = - 16.88819 \dots

Solution steps

x^{2} + 16 x - 11 = 4

Move

4

to the left side

x^{2} + 16 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 15) = 279

x_{1, 2} = \frac{- 16 \pm 2 79}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 79}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 79}{2 \cdot 1}

x = \frac{- 16 + 2 79}{2 \cdot 1} : - 8 + 79

x = \frac{- 16 - 2 79}{2 \cdot 1} : - 8 - 79

The solutions to the quadratic equation are:

x = - 8 + 79, x = - 8 - 79

2 x^{2} - 196 x - 960 = 0

s^{2} + 1.2 s + 0.2924

5 z^{2} + 8 z + 5 = 0

x^{2} - 7 x + 27 = 15

- x^{2} - 8 x + 20 = 0

What are the solutions to the equation x^2+16x-11=4 ?
The solutions to the equation x^2+16x-11=4 are x=-8+sqrt(79),x=-8-sqrt(79)
Find the zeros of x^2+16x-11=4
The zeros of x^2+16x-11=4 are x=-8+sqrt(79),x=-8-sqrt(79)