What are the solutions to the equation solvefor t,u=t^2+2 ?

The solutions to the equation solvefor t,u=t^2+2 are t=sqrt(u-2),t=-sqrt(u-2)

Find the zeros of solvefor t,u=t^2+2

The zeros of solvefor t,u=t^2+2 are t=sqrt(u-2),t=-sqrt(u-2)

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solve for

t, u = t^{2} + 2

t = u - 2, t = - u - 2

Solution steps

u = t^{2} + 2

Switch sides

t^{2} + 2 = u

Move

2

to the right side

t^{2} = u - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = u - 2, t = - u - 2

18 = 0.9 x^{2} - 3 x + 3

x^{2} + 4 x + 6 = 0

5 + 4 x - x^{2}

x^{2} + (- x)^{2} = 1

2 (x - 3)^{2} = 0

What are the solutions to the equation solvefor t,u=t^2+2 ?
The solutions to the equation solvefor t,u=t^2+2 are t=sqrt(u-2),t=-sqrt(u-2)
Find the zeros of solvefor t,u=t^2+2
The zeros of solvefor t,u=t^2+2 are t=sqrt(u-2),t=-sqrt(u-2)