What are the solutions to the equation x^2+8x-96=0 ?

The solutions to the equation x^2+8x-96=0 are x=4(sqrt(7)-1),x=-4(1+sqrt(7))

Find the zeros of x^2+8x-96=0

The zeros of x^2+8x-96=0 are x=4(sqrt(7)-1),x=-4(1+sqrt(7))

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x^{2} + 8 x - 96 = 0

x = 4 (7 - 1), x = - 4 (1 + 7)

Decimal Notation

x = 6.58300 \dots, x = - 14.58300 \dots

Solution steps

x^{2} + 8 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 96 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 96) = 87

x_{1, 2} = \frac{- 8 \pm 8 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 7}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 7}{2 \cdot 1}

x = \frac{- 8 + 8 7}{2 \cdot 1} : 4 (7 - 1)

x = \frac{- 8 - 8 7}{2 \cdot 1} : - 4 (1 + 7)

The solutions to the quadratic equation are:

x = 4 (7 - 1), x = - 4 (1 + 7)

- 26 x + 8 x^{2} = 24

3 x^{2} + 9 x - 7 = 0

4 x^{2} - 8 x + 6

6 u^{2} + 30 u = 0

x^{2} = \frac{3}{25}

What are the solutions to the equation x^2+8x-96=0 ?
The solutions to the equation x^2+8x-96=0 are x=4(sqrt(7)-1),x=-4(1+sqrt(7))
Find the zeros of x^2+8x-96=0
The zeros of x^2+8x-96=0 are x=4(sqrt(7)-1),x=-4(1+sqrt(7))