What are the solutions to the equation -26x+8x^2=24 ?

The solutions to the equation -26x+8x^2=24 are x=4,x=-3/4

Find the zeros of -26x+8x^2=24

The zeros of -26x+8x^2=24 are x=4,x=-3/4

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- 26 x + 8 x^{2} = 24

x = 4, x = - \frac{3}{4}

Decimal Notation

x = 4, x = - 0.75

Solution steps

- 26 x + 8 x^{2} = 24

Move

24

to the left side

- 26 x + 8 x^{2} - 24 = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} - 26 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 8 ( - 24 )}{2 \cdot 8}

(- 26)^{2} - 4 \cdot 8 (- 24) = 38

x_{1, 2} = \frac{- ( - 26 ) \pm 38}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 38}{2 \cdot 8}, x_{2} = \frac{- ( - 26 ) - 38}{2 \cdot 8}

x = \frac{- ( - 26 ) + 38}{2 \cdot 8} : 4

x = \frac{- ( - 26 ) - 38}{2 \cdot 8} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 4, x = - \frac{3}{4}

3 x^{2} + 9 x - 7 = 0

4 x^{2} - 8 x + 6

6 u^{2} + 30 u = 0

x^{2} = \frac{3}{25}

x^{2} + 8 x + 15 = 0

What are the solutions to the equation -26x+8x^2=24 ?
The solutions to the equation -26x+8x^2=24 are x=4,x=-3/4
Find the zeros of -26x+8x^2=24
The zeros of -26x+8x^2=24 are x=4,x=-3/4