What are the solutions to the equation (x^2-x-6)=0 ?

The solutions to the equation (x^2-x-6)=0 are x=-2,x=3

Find the zeros of (x^2-x-6)=0

The zeros of (x^2-x-6)=0 are x=-2,x=3

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(x^{2} - x - 6) = 0

x = - 2, x = 3

Solution steps

(x^{2} - x - 6) = 0

Factor

x^{2} - x - 6 : (x + 2) (x - 3)

(x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 2, x = 3

1 x^{2} - 1 x - 2 = 0

n^{2} - n - 5 = - 2 n^{2} - 2 n^{2}

(0.036 - x) (7.1 \times 1 0^{- 4}) = x^{2}

2 x^{2} + 16 x + 26 = 0

6 0^{2} + 8 0^{2} = x^{2}

What are the solutions to the equation (x^2-x-6)=0 ?
The solutions to the equation (x^2-x-6)=0 are x=-2,x=3
Find the zeros of (x^2-x-6)=0
The zeros of (x^2-x-6)=0 are x=-2,x=3