What are the solutions to the equation y^2-2y-6=0 ?

The solutions to the equation y^2-2y-6=0 are y=1+sqrt(7),y=1-sqrt(7)

Find the zeros of y^2-2y-6=0

The zeros of y^2-2y-6=0 are y=1+sqrt(7),y=1-sqrt(7)

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y^{2} - 2 y - 6 = 0

y = 1 + 7, y = 1 - 7

Decimal Notation

y = 3.64575 \dots, y = - 1.64575 \dots

Solution steps

y^{2} - 2 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 6) = 27

y_{1, 2} = \frac{- ( - 2 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 7}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 7}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 7}{2 \cdot 1} : 1 + 7

y = \frac{- ( - 2 ) - 2 7}{2 \cdot 1} : 1 - 7

The solutions to the quadratic equation are:

y = 1 + 7, y = 1 - 7

- 2 x^{2} + 16 x - 31 = 0

\frac{x ^{2} + 5 x}{2} = 102

(x + 2)^{2} = 144

x^{2} + 8 x - 1

x^{2} + 8 x - 9

What are the solutions to the equation y^2-2y-6=0 ?
The solutions to the equation y^2-2y-6=0 are y=1+sqrt(7),y=1-sqrt(7)
Find the zeros of y^2-2y-6=0
The zeros of y^2-2y-6=0 are y=1+sqrt(7),y=1-sqrt(7)