What are the solutions to the equation -32x^2+98=0 ?

The solutions to the equation -32x^2+98=0 are x= 7/4 ,x=-7/4

Find the zeros of -32x^2+98=0

The zeros of -32x^2+98=0 are x= 7/4 ,x=-7/4

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- 32 x^{2} + 98 = 0

x = \frac{7}{4}, x = - \frac{7}{4}

Decimal Notation

x = 1.75, x = - 1.75

Solution steps

- 32 x^{2} + 98 = 0

Move

98

to the right side

- 32 x^{2} = - 98

Divide both sides by

- 32

x^{2} = \frac{49}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{49}{16}, x = - \frac{49}{16}

\frac{49}{16} = \frac{7}{4}

- \frac{49}{16} = - \frac{7}{4}

x = \frac{7}{4}, x = - \frac{7}{4}

3 z^{2} + 6 z + 3 = 0

r, r^{2} - 2 r + 2 = 0

x = \frac{1}{2} (0.004) (5 - 5000 x - 0.3)^{2}

x, x^{2} y^{2} - 16 x y^{2} + 64 y^{2} = x^{2} + 2 x - 15

0 = 12 x^{2} - 84 x + 104

What are the solutions to the equation -32x^2+98=0 ?
The solutions to the equation -32x^2+98=0 are x= 7/4 ,x=-7/4
Find the zeros of -32x^2+98=0
The zeros of -32x^2+98=0 are x= 7/4 ,x=-7/4