What are the solutions to the equation x^2-10x+25=-16+25 ?

The solutions to the equation x^2-10x+25=-16+25 are x=8,x=2

Find the zeros of x^2-10x+25=-16+25

The zeros of x^2-10x+25=-16+25 are x=8,x=2

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x^{2} - 10 x + 25 = - 16 + 25

x = 8, x = 2

Solution steps

x^{2} - 10 x + 25 = - 16 + 25

Refine

x^{2} - 10 x + 25 = 9

Move

9

to the left side

x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

x = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 8, x = 2

\frac{- 1}{6} x^{2} + x - 3 = 0

- 21 x^{2} + 31 x + 26 = 0

6 x^{2} + 240 = 0

2 0^{2} + 15 6^{2} = x^{2}

4 x^{2} - 6 = - 12 x

What are the solutions to the equation x^2-10x+25=-16+25 ?
The solutions to the equation x^2-10x+25=-16+25 are x=8,x=2
Find the zeros of x^2-10x+25=-16+25
The zeros of x^2-10x+25=-16+25 are x=8,x=2