What are the solutions to the equation 3(x-2)^2+8=2 ?

The solutions to the equation 3(x-2)^2+8=2 are x=sqrt(2)i+2,x=-sqrt(2)i+2

Find the zeros of 3(x-2)^2+8=2

The zeros of 3(x-2)^2+8=2 are x=sqrt(2)i+2,x=-sqrt(2)i+2

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3 (x - 2)^{2} + 8 = 2

x = 2 i + 2, x = - 2 i + 2

Solution steps

3 (x - 2)^{2} + 8 = 2

Move

8

to the right side

3 (x - 2)^{2} = - 6

Divide both sides by

3

(x - 2)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 2 : x = 2 i + 2

Solve

x - 2 = - - 2 : x = - 2 i + 2

The solutions to the quadratic equation are:

x = 2 i + 2, x = - 2 i + 2

x^{2} = - 19 x

5 p^{2} - 5 = 2 p

x, F = x + (x^{2} + x y + 1) y

x^{2} = - 112

n^{2} = - 43

What are the solutions to the equation 3(x-2)^2+8=2 ?
The solutions to the equation 3(x-2)^2+8=2 are x=sqrt(2)i+2,x=-sqrt(2)i+2
Find the zeros of 3(x-2)^2+8=2
The zeros of 3(x-2)^2+8=2 are x=sqrt(2)i+2,x=-sqrt(2)i+2