What are the solutions to the equation 2x^2+3=69 ?

The solutions to the equation 2x^2+3=69 are x=sqrt(33),x=-sqrt(33)

Find the zeros of 2x^2+3=69

The zeros of 2x^2+3=69 are x=sqrt(33),x=-sqrt(33)

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2 x^{2} + 3 = 69

x = 33, x = - 33

Decimal Notation

x = 5.74456 \dots, x = - 5.74456 \dots

Solution steps

2 x^{2} + 3 = 69

Move

3

to the right side

2 x^{2} = 66

Divide both sides by

2

x^{2} = 33

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 33, x = - 33

w^{2} - 7 w - 18 = 0

4 n^{2} + 24 n + 20 = 0

6 x^{2} - 14 x + 4 = 0

x, F = (x^{2} + x y - 1) y - x

x, x^{2} + 6 m x + m = 0

What are the solutions to the equation 2x^2+3=69 ?
The solutions to the equation 2x^2+3=69 are x=sqrt(33),x=-sqrt(33)
Find the zeros of 2x^2+3=69
The zeros of 2x^2+3=69 are x=sqrt(33),x=-sqrt(33)