What are the solutions to the equation 4n^2+24n+20=0 ?

The solutions to the equation 4n^2+24n+20=0 are n=-1,n=-5

Find the zeros of 4n^2+24n+20=0

The zeros of 4n^2+24n+20=0 are n=-1,n=-5

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4 n^{2} + 24 n + 20 = 0

n = - 1, n = - 5

Solution steps

4 n^{2} + 24 n + 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 20}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 20 = 16

n_{1, 2} = \frac{- 24 \pm 16}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- 24 + 16}{2 \cdot 4}, n_{2} = \frac{- 24 - 16}{2 \cdot 4}

n = \frac{- 24 + 16}{2 \cdot 4} : - 1

n = \frac{- 24 - 16}{2 \cdot 4} : - 5

The solutions to the quadratic equation are:

n = - 1, n = - 5

6 x^{2} - 14 x + 4 = 0

x, F = (x^{2} + x y - 1) y - x

x, x^{2} + 6 m x + m = 0

x^{2} = 1 2^{2} + 1 3^{2}

x = x^{2} - 24 x + 144

What are the solutions to the equation 4n^2+24n+20=0 ?
The solutions to the equation 4n^2+24n+20=0 are n=-1,n=-5
Find the zeros of 4n^2+24n+20=0
The zeros of 4n^2+24n+20=0 are n=-1,n=-5