What are the solutions to the equation w^2-9w+18=0 ?

The solutions to the equation w^2-9w+18=0 are w=6,w=3

Find the zeros of w^2-9w+18=0

The zeros of w^2-9w+18=0 are w=6,w=3

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w^{2} - 9 w + 18 = 0

w = 6, w = 3

Solution steps

w^{2} - 9 w + 18 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

w_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, w_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

w = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

w = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

w = 6, w = 3

2 x^{2} - h x + 2 k = 0

3 v^{2} + 6 v + 3 = 0

r^{2} + 10 r + 50 = 0

49 + 16 m^{2} - 256 m = 0

- 4 + z^{2} = 16

What are the solutions to the equation w^2-9w+18=0 ?
The solutions to the equation w^2-9w+18=0 are w=6,w=3
Find the zeros of w^2-9w+18=0
The zeros of w^2-9w+18=0 are w=6,w=3