What are the solutions to the equation x^2-0.2x+0.51=0 ?

The solutions to the equation x^2-0.2x+0.51=0 are x= 1/10+i(sqrt(2))/2 ,x= 1/10-i(sqrt(2))/2

Find the zeros of x^2-0.2x+0.51=0

The zeros of x^2-0.2x+0.51=0 are x= 1/10+i(sqrt(2))/2 ,x= 1/10-i(sqrt(2))/2

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x^{2} - 0.2 x + 0.51 = 0

x = \frac{1}{10} + i \frac{2}{2}, x = \frac{1}{10} - i \frac{2}{2}

Solution steps

x^{2} - 0.2 x + 0.51 = 0

Multiply both sides by

100

100 x^{2} - 20 x + 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 100 \cdot 51}{2 \cdot 100}

Simplify

(- 20)^{2} - 4 \cdot 100 \cdot 51 : 1002 i

x_{1, 2} = \frac{- ( - 20 ) \pm 100 2 i}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 100 2 i}{2 \cdot 100}, x_{2} = \frac{- ( - 20 ) - 100 2 i}{2 \cdot 100}

x = \frac{- ( - 20 ) + 100 2 i}{2 \cdot 100} : \frac{1}{10} + i \frac{2}{2}

x = \frac{- ( - 20 ) - 100 2 i}{2 \cdot 100} : \frac{1}{10} - i \frac{2}{2}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{2}{2}, x = \frac{1}{10} - i \frac{2}{2}

r^{2} + 8 r + 5 = 0

6 x^{2} - 7 x - 24 = 0

(3 - x) (2 - x) - 12 = 0

1400 - 3 x^{2} = 0

t^{2} - 3 t - 40 = 0

What are the solutions to the equation x^2-0.2x+0.51=0 ?
The solutions to the equation x^2-0.2x+0.51=0 are x= 1/10+i(sqrt(2))/2 ,x= 1/10-i(sqrt(2))/2
Find the zeros of x^2-0.2x+0.51=0
The zeros of x^2-0.2x+0.51=0 are x= 1/10+i(sqrt(2))/2 ,x= 1/10-i(sqrt(2))/2