What are the solutions to the equation 6x^2-11x+6=0 ?

The solutions to the equation 6x^2-11x+6=0 are x= 11/12+i(sqrt(23))/(12),x= 11/12-i(sqrt(23))/(12)

Find the zeros of 6x^2-11x+6=0

The zeros of 6x^2-11x+6=0 are x= 11/12+i(sqrt(23))/(12),x= 11/12-i(sqrt(23))/(12)

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6 x^{2} - 11 x + 6 = 0

x = \frac{11}{12} + i \frac{23}{12}, x = \frac{11}{12} - i \frac{23}{12}

Solution steps

6 x^{2} - 11 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

Simplify

(- 11)^{2} - 4 \cdot 6 \cdot 6 : 23 i

x_{1, 2} = \frac{- ( - 11 ) \pm 23 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 23 i}{2 \cdot 6}, x_{2} = \frac{- ( - 11 ) - 23 i}{2 \cdot 6}

x = \frac{- ( - 11 ) + 23 i}{2 \cdot 6} : \frac{11}{12} + i \frac{23}{12}

x = \frac{- ( - 11 ) - 23 i}{2 \cdot 6} : \frac{11}{12} - i \frac{23}{12}

The solutions to the quadratic equation are:

x = \frac{11}{12} + i \frac{23}{12}, x = \frac{11}{12} - i \frac{23}{12}

(3 x - 1) (2 x) + (2 x) = 0

2 a^{2} + 15 a + 7 = 0

x^{2} - 0.4 x - 1.2 = 0

2 x (x + 5) = 45

D, (x^{2} D^{2} - 4 x D - 6 I) y = 0

What are the solutions to the equation 6x^2-11x+6=0 ?
The solutions to the equation 6x^2-11x+6=0 are x= 11/12+i(sqrt(23))/(12),x= 11/12-i(sqrt(23))/(12)
Find the zeros of 6x^2-11x+6=0
The zeros of 6x^2-11x+6=0 are x= 11/12+i(sqrt(23))/(12),x= 11/12-i(sqrt(23))/(12)