What are the solutions to the equation m^2-12m+2=0 ?

The solutions to the equation m^2-12m+2=0 are m=6+sqrt(34),m=6-sqrt(34)

Find the zeros of m^2-12m+2=0

The zeros of m^2-12m+2=0 are m=6+sqrt(34),m=6-sqrt(34)

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m^{2} - 12 m + 2 = 0

m = 6 + 34, m = 6 - 34

Decimal Notation

m = 11.83095 \dots, m = 0.16904 \dots

Solution steps

m^{2} - 12 m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 2 = 234

m_{1, 2} = \frac{- ( - 12 ) \pm 2 34}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 12 ) + 2 34}{2 \cdot 1}, m_{2} = \frac{- ( - 12 ) - 2 34}{2 \cdot 1}

m = \frac{- ( - 12 ) + 2 34}{2 \cdot 1} : 6 + 34

m = \frac{- ( - 12 ) - 2 34}{2 \cdot 1} : 6 - 34

The solutions to the quadratic equation are:

m = 6 + 34, m = 6 - 34

\frac{9.81}{2} x^{2} + 9.81 x - \frac{3 ( 33.1 8 ^{2} )}{4} = 0

10 k^{2} + 2 = - 63

x^{2} - x = 2 x

3 x (x - 2) + 9 (x - 2) = 0

x^{2} + a x + b

What are the solutions to the equation m^2-12m+2=0 ?
The solutions to the equation m^2-12m+2=0 are m=6+sqrt(34),m=6-sqrt(34)
Find the zeros of m^2-12m+2=0
The zeros of m^2-12m+2=0 are m=6+sqrt(34),m=6-sqrt(34)