What are the solutions to the equation x^2-x=2x ?

The solutions to the equation x^2-x=2x are x=3,x=0

Find the zeros of x^2-x=2x

The zeros of x^2-x=2x are x=3,x=0

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x^{2} - x = 2 x

x = 3, x = 0

Solution steps

x^{2} - x = 2 x

Move

2 x

to the left side

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

3 x (x - 2) + 9 (x - 2) = 0

x^{2} + a x + b

k^{2} - k - 56 = 0

r^{2} = 3^{2} + (- 4)^{2}

x, (f \circ g) = (π - x)^{2} - π

What are the solutions to the equation x^2-x=2x ?
The solutions to the equation x^2-x=2x are x=3,x=0
Find the zeros of x^2-x=2x
The zeros of x^2-x=2x are x=3,x=0