What are the solutions to the equation 2p^2-5p=3 ?

The solutions to the equation 2p^2-5p=3 are p=3,p=-1/2

Find the zeros of 2p^2-5p=3

The zeros of 2p^2-5p=3 are p=3,p=-1/2

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2 p^{2} - 5 p = 3

p = 3, p = - \frac{1}{2}

Decimal Notation

p = 3, p = - 0.5

Solution steps

2 p^{2} - 5 p = 3

Move

3

to the left side

2 p^{2} - 5 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

p_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, p_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

p = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

p = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

p = 3, p = - \frac{1}{2}

40 = 10 x - x^{2}

4 x^{2} - 12 x - 9 + 3 = 0

1 0^{2} + 10 0^{2} = c^{2}

t, 5 t^{2} - 9 = 0

s^{2}

What are the solutions to the equation 2p^2-5p=3 ?
The solutions to the equation 2p^2-5p=3 are p=3,p=-1/2
Find the zeros of 2p^2-5p=3
The zeros of 2p^2-5p=3 are p=3,p=-1/2