What are the solutions to the equation 4y^2+3y-22=0 ?

The solutions to the equation 4y^2+3y-22=0 are y=2,y=-11/4

Find the zeros of 4y^2+3y-22=0

The zeros of 4y^2+3y-22=0 are y=2,y=-11/4

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4 y^{2} + 3 y - 22 = 0

y = 2, y = - \frac{11}{4}

Decimal Notation

y = 2, y = - 2.75

Solution steps

4 y^{2} + 3 y - 22 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 22 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 22) = 19

y_{1, 2} = \frac{- 3 \pm 19}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- 3 + 19}{2 \cdot 4}, y_{2} = \frac{- 3 - 19}{2 \cdot 4}

y = \frac{- 3 + 19}{2 \cdot 4} : 2

y = \frac{- 3 - 19}{2 \cdot 4} : - \frac{11}{4}

The solutions to the quadratic equation are:

y = 2, y = - \frac{11}{4}

- 22 x^{2} + 8 = 0

n^{2} - 18 n + 91 = 0

x, k x^{2} + 8 x + 2 k = 0

x, x^{2} - 4 x y - 2 y^{2} - 3 = 0

2 (x + 4) = - (2 x - 3)^{2}

What are the solutions to the equation 4y^2+3y-22=0 ?
The solutions to the equation 4y^2+3y-22=0 are y=2,y=-11/4
Find the zeros of 4y^2+3y-22=0
The zeros of 4y^2+3y-22=0 are y=2,y=-11/4