What are the solutions to the equation x^2-2sqrt(3)x+1=0 ?

The solutions to the equation x^2-2sqrt(3)x+1=0 are x=sqrt(3)+sqrt(2),x=sqrt(3)-sqrt(2)

Find the zeros of x^2-2sqrt(3)x+1=0

The zeros of x^2-2sqrt(3)x+1=0 are x=sqrt(3)+sqrt(2),x=sqrt(3)-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 23 x + 1 = 0

x = 3 + 2, x = 3 - 2

Decimal Notation

x = 3.14626 \dots, x = 0.31783 \dots

Solution steps

x^{2} - 23 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 3 ) \pm ( - 2 3 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 23)^{2} - 4 \cdot 1 \cdot 1 = 22

x_{1, 2} = \frac{- ( - 2 3 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 3 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 3 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 2 3 ) + 2 2}{2 \cdot 1} : 3 + 2

x = \frac{- ( - 2 3 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

x = 3 + 2, x = 3 - 2

(8 t - 7) (3 t + 5) = 0

x^{2} = 4^{2} + 5^{2}

3 y^{2} - 5 - y^{2} = 3

- 0.125 x^{2} + 0.5 x + 5.5 = 0

(5 y + 6)^{2} = 24

What are the solutions to the equation x^2-2sqrt(3)x+1=0 ?
The solutions to the equation x^2-2sqrt(3)x+1=0 are x=sqrt(3)+sqrt(2),x=sqrt(3)-sqrt(2)
Find the zeros of x^2-2sqrt(3)x+1=0
The zeros of x^2-2sqrt(3)x+1=0 are x=sqrt(3)+sqrt(2),x=sqrt(3)-sqrt(2)