What are the solutions to the equation 25^2=x^2+20^2 ?

The solutions to the equation 25^2=x^2+20^2 are x=15,x=-15

Find the zeros of 25^2=x^2+20^2

The zeros of 25^2=x^2+20^2 are x=15,x=-15

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2 5^{2} = x^{2} + 2 0^{2}

x = 15, x = - 15

Solution steps

2 5^{2} = x^{2} + 2 0^{2}

Switch sides

x^{2} + 2 0^{2} = 2 5^{2}

Move

2 0^{2}

to the right side

x^{2} = 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 225, x = - 225

225 = 15

- 225 = - 15

x = 15, x = - 15

5 m^{2} - 2 m = 6

a^{2} 3 = 3

x^{2} - 60 = 0

k^{2} - 2 k - 7 = 0

18 x^{2} + 6 x + 1 = 0

What are the solutions to the equation 25^2=x^2+20^2 ?
The solutions to the equation 25^2=x^2+20^2 are x=15,x=-15
Find the zeros of 25^2=x^2+20^2
The zeros of 25^2=x^2+20^2 are x=15,x=-15