What are the solutions to the equation ln(2)(-8x^2+41)=0 ?

The solutions to the equation ln(2)(-8x^2+41)=0 are x=(sqrt(41))/(2sqrt(2)),x=-(sqrt(41))/(2sqrt(2))

Find the zeros of ln(2)(-8x^2+41)=0

The zeros of ln(2)(-8x^2+41)=0 are x=(sqrt(41))/(2sqrt(2)),x=-(sqrt(41))/(2sqrt(2))

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ln (2) (- 8 x^{2} + 41) = 0

x = \frac{41}{2 2}, x = - \frac{41}{2 2}

Decimal Notation

x = 2.26384 \dots, x = - 2.26384 \dots

Solution steps

ln (2) (- 8 x^{2} + 41) = 0

Divide both sides by

ln (2)

- 8 x^{2} + 41 = 0

Move

41

to the right side

- 8 x^{2} = - 41

Divide both sides by

- 8

x^{2} = \frac{41}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{41}{8}, x = - \frac{41}{8}

\frac{41}{8} = \frac{41}{2 2}

- \frac{41}{8} = - \frac{41}{2 2}

x = \frac{41}{2 2}, x = - \frac{41}{2 2}

\frac{2}{3} x \frac{- 1}{9} x + 5 = 20

0 = 2 (x + 2)^{2} - 1

v^{2} + 10 v + 15 = - 6

6 t^{2} - 5 t - 9 = 0

3 x^{2} = 49

What are the solutions to the equation ln(2)(-8x^2+41)=0 ?
The solutions to the equation ln(2)(-8x^2+41)=0 are x=(sqrt(41))/(2sqrt(2)),x=-(sqrt(41))/(2sqrt(2))
Find the zeros of ln(2)(-8x^2+41)=0
The zeros of ln(2)(-8x^2+41)=0 are x=(sqrt(41))/(2sqrt(2)),x=-(sqrt(41))/(2sqrt(2))