What are the solutions to the equation 19m^2+5m-12=6m^2 ?

The solutions to the equation 19m^2+5m-12=6m^2 are m=(-5+sqrt(649))/(26),m=(-5-sqrt(649))/(26)

Find the zeros of 19m^2+5m-12=6m^2

The zeros of 19m^2+5m-12=6m^2 are m=(-5+sqrt(649))/(26),m=(-5-sqrt(649))/(26)

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19 m^{2} + 5 m - 12 = 6 m^{2}

m = \frac{- 5 + 649}{26}, m = \frac{- 5 - 649}{26}

Decimal Notation

m = 0.78751 \dots, m = - 1.17213 \dots

Solution steps

19 m^{2} + 5 m - 12 = 6 m^{2}

Move

6 m^{2}

to the left side

13 m^{2} + 5 m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 13 ( - 12 )}{2 \cdot 13}

5^{2} - 4 \cdot 13 (- 12) = 649

m_{1, 2} = \frac{- 5 \pm 649}{2 \cdot 13}

Separate the solutions

m_{1} = \frac{- 5 + 649}{2 \cdot 13}, m_{2} = \frac{- 5 - 649}{2 \cdot 13}

m = \frac{- 5 + 649}{2 \cdot 13} : \frac{- 5 + 649}{26}

m = \frac{- 5 - 649}{2 \cdot 13} : \frac{- 5 - 649}{26}

The solutions to the quadratic equation are:

m = \frac{- 5 + 649}{26}, m = \frac{- 5 - 649}{26}

a, - 2 a^{2} + 11 ab - 5 b^{2} = 0

9 x^{2} - 17 x = 2

x^{2} + 4 x + \frac{15}{4} = 0

g^{2} + 2 g - 15 = 0

5 r^{2} - 5 r = - 8

What are the solutions to the equation 19m^2+5m-12=6m^2 ?
The solutions to the equation 19m^2+5m-12=6m^2 are m=(-5+sqrt(649))/(26),m=(-5-sqrt(649))/(26)
Find the zeros of 19m^2+5m-12=6m^2
The zeros of 19m^2+5m-12=6m^2 are m=(-5+sqrt(649))/(26),m=(-5-sqrt(649))/(26)