What are the solutions to the equation 2a^2x^2-6ax=-5 ?

The solutions to the equation 2a^2x^2-6ax=-5 are x= 3/(2a)+i 1/(2a),x= 3/(2a)-i 1/(2a);\quad a\ne 0

Find the zeros of 2a^2x^2-6ax=-5

The zeros of 2a^2x^2-6ax=-5 are x= 3/(2a)+i 1/(2a),x= 3/(2a)-i 1/(2a);\quad a\ne 0

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2 a^{2} x^{2} - 6 a x = - 5

x = \frac{3}{2 a} + i \frac{1}{2 a}, x = \frac{3}{2 a} - i \frac{1}{2 a}; a \neq = 0

Solution steps

2 a^{2} x^{2} - 6 a x = - 5

Move

5

to the left side

2 a^{2} x^{2} - 6 a x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 a ) \pm ( - 6 a ) ^{2} - 4 \cdot 2 a ^{2} \cdot 5}{2 \cdot 2 a ^{2}}

Simplify

(- 6 a)^{2} - 4 \cdot 2 a^{2} \cdot 5 : 2 ia

x_{1, 2} = \frac{- ( - 6 a ) \pm 2 ia}{2 \cdot 2 a ^{2}}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( - 6 a ) + 2 ia}{2 \cdot 2 a ^{2}}, x_{2} = \frac{- ( - 6 a ) - 2 ia}{2 \cdot 2 a ^{2}}

x = \frac{- ( - 6 a ) + 2 ia}{2 \cdot 2 a ^{2}} : \frac{3}{2 a} + i \frac{1}{2 a}

x = \frac{- ( - 6 a ) - 2 ia}{2 \cdot 2 a ^{2}} : \frac{3}{2 a} - i \frac{1}{2 a}

The solutions to the quadratic equation are:

x = \frac{3}{2 a} + i \frac{1}{2 a}, x = \frac{3}{2 a} - i \frac{1}{2 a}; a \neq = 0

2 u^{2} - 7 u = 0

5 m^{2} + 26 m + 5 = 0

2 x^{2} - x (- 2) + (- 2)^{2} = 8

x, 2 x^{2} - 10 x - 28 = 0

0 = 2 x^{2} - 4 x + 2

What are the solutions to the equation 2a^2x^2-6ax=-5 ?
The solutions to the equation 2a^2x^2-6ax=-5 are x= 3/(2a)+i 1/(2a),x= 3/(2a)-i 1/(2a);\quad a\ne 0
Find the zeros of 2a^2x^2-6ax=-5
The zeros of 2a^2x^2-6ax=-5 are x= 3/(2a)+i 1/(2a),x= 3/(2a)-i 1/(2a);\quad a\ne 0