What are the solutions to the equation 2u^2-7u=0 ?

The solutions to the equation 2u^2-7u=0 are u= 7/2 ,u=0

Find the zeros of 2u^2-7u=0

The zeros of 2u^2-7u=0 are u= 7/2 ,u=0

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2 u^{2} - 7 u = 0

u = \frac{7}{2}, u = 0

Decimal Notation

u = 3.5, u = 0

Solution steps

2 u^{2} - 7 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 0 = 7

u_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 2}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 2}, u_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 2}

u = \frac{- ( - 7 ) + 7}{2 \cdot 2} : \frac{7}{2}

u = \frac{- ( - 7 ) - 7}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

u = \frac{7}{2}, u = 0

5 m^{2} + 26 m + 5 = 0

2 x^{2} - x (- 2) + (- 2)^{2} = 8

x, 2 x^{2} - 10 x - 28 = 0

0 = 2 x^{2} - 4 x + 2

4 = 2 x^{2} - x + 3

What are the solutions to the equation 2u^2-7u=0 ?
The solutions to the equation 2u^2-7u=0 are u= 7/2 ,u=0
Find the zeros of 2u^2-7u=0
The zeros of 2u^2-7u=0 are u= 7/2 ,u=0