What are the solutions to the equation x^2+9x+3=0 ?

The solutions to the equation x^2+9x+3=0 are x=(-9+sqrt(69))/2 ,x=(-9-sqrt(69))/2

Find the zeros of x^2+9x+3=0

The zeros of x^2+9x+3=0 are x=(-9+sqrt(69))/2 ,x=(-9-sqrt(69))/2

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x^{2} + 9 x + 3 = 0

x = \frac{- 9 + 69}{2}, x = \frac{- 9 - 69}{2}

Solution steps

x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 3 = 69

x_{1, 2} = \frac{- 9 \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 69}{2 \cdot 1}, x_{2} = \frac{- 9 - 69}{2 \cdot 1}

x = \frac{- 9 + 69}{2 \cdot 1} : \frac{- 9 + 69}{2}

x = \frac{- 9 - 69}{2 \cdot 1} : \frac{- 9 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 69}{2}, x = \frac{- 9 - 69}{2}

\frac{2 ^{- 3}}{5 ^{0}}

x^{2} + 3 x - 15 = 3

e^{2 x} e^{2 x}

32 x^{2} + 16 x + 2 = 0

3 x^{2} - 14 x + 16

What are the solutions to the equation x^2+9x+3=0 ?
The solutions to the equation x^2+9x+3=0 are x=(-9+sqrt(69))/2 ,x=(-9-sqrt(69))/2
Find the zeros of x^2+9x+3=0
The zeros of x^2+9x+3=0 are x=(-9+sqrt(69))/2 ,x=(-9-sqrt(69))/2