What are the solutions to the equation 0=x^2+4x-2 ?

The solutions to the equation 0=x^2+4x-2 are x=-2+sqrt(6),x=-2-sqrt(6)

Find the zeros of 0=x^2+4x-2

The zeros of 0=x^2+4x-2 are x=-2+sqrt(6),x=-2-sqrt(6)

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0 = x^{2} + 4 x - 2

x = - 2 + 6, x = - 2 - 6

Solution steps

0 = x^{2} + 4 x - 2

Switch sides

x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 2) = 26

x_{1, 2} = \frac{- 4 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 6}{2 \cdot 1}

x = \frac{- 4 + 2 6}{2 \cdot 1} : - 2 + 6

x = \frac{- 4 - 2 6}{2 \cdot 1} : - 2 - 6

The solutions to the quadratic equation are:

x = - 2 + 6, x = - 2 - 6

lo g_{10} (0.0001)

\frac{3 x - 3}{4} \geq 6

\frac{3 x ^{9}}{6 y ^{- 2}} \cdot \frac{12 y ^{- 3}}{4 x}

w^{2} - 4 = 0

\frac{4}{10} x - 4 x + \frac{6}{5} = \frac{4}{5}

What are the solutions to the equation 0=x^2+4x-2 ?
The solutions to the equation 0=x^2+4x-2 are x=-2+sqrt(6),x=-2-sqrt(6)
Find the zeros of 0=x^2+4x-2
The zeros of 0=x^2+4x-2 are x=-2+sqrt(6),x=-2-sqrt(6)