What are the solutions to the equation 0=-16t^2+69t+9 ?

The solutions to the equation 0=-16t^2+69t+9 are t=-(-69+3sqrt(593))/(32),t=(69+3sqrt(593))/(32)

Find the zeros of 0=-16t^2+69t+9

The zeros of 0=-16t^2+69t+9 are t=-(-69+3sqrt(593))/(32),t=(69+3sqrt(593))/(32)

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0 = - 16 t^{2} + 69 t + 9

t = - \frac{- 69 + 3 593}{32}, t = \frac{69 + 3 593}{32}

Decimal Notation

t = - 0.12671 \dots, t = 4.43921 \dots

Solution steps

0 = - 16 t^{2} + 69 t + 9

Switch sides

- 16 t^{2} + 69 t + 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 69 \pm 6 9 ^{2} - 4 ( - 16 ) \cdot 9}{2 ( - 16 )}

6 9^{2} - 4 (- 16) \cdot 9 = 3593

t_{1, 2} = \frac{- 69 \pm 3 593}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 69 + 3 593}{2 ( - 16 )}, t_{2} = \frac{- 69 - 3 593}{2 ( - 16 )}

t = \frac{- 69 + 3 593}{2 ( - 16 )} : - \frac{- 69 + 3 593}{32}

t = \frac{- 69 - 3 593}{2 ( - 16 )} : \frac{69 + 3 593}{32}

The solutions to the quadratic equation are:

t = - \frac{- 69 + 3 593}{32}, t = \frac{69 + 3 593}{32}

\frac{8 !}{3 ! 5 !}

4 m^{2} + m + 6 = 2

(- 26 - x) (- 44 - x) - 40 \cdot 40 = 0

x^{5} - 6 x^{4} - 12 x^{3} + 82 x^{2} - 45 x + 300

\frac{∣ m ∣}{5} = 3

What are the solutions to the equation 0=-16t^2+69t+9 ?
The solutions to the equation 0=-16t^2+69t+9 are t=-(-69+3sqrt(593))/(32),t=(69+3sqrt(593))/(32)
Find the zeros of 0=-16t^2+69t+9
The zeros of 0=-16t^2+69t+9 are t=-(-69+3sqrt(593))/(32),t=(69+3sqrt(593))/(32)