What is -4|x-6|>=-20 ?

The solution to -4|x-6|>=-20 is 1<= x<= 11

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-4|x-6|>=-20

- 4 ∣ x - 6 ∣ \geq - 20

1 \leq x \leq 11

Interval Notation

[1, 11]

Solution steps

- 4 ∣ x - 6 ∣ \geq - 20

Multiply both sides by

- 1

4 ∣ x - 6 ∣ \leq 20

Divide both sides by

4

∣ x - 6 ∣ \leq 5

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 5 \leq x - 6 \leq 5

x - 6 \geq - 5 and x - 6 \leq 5

x \geq 1 and x \leq 11

Merge Overlapping Intervals

1 \leq x \leq 11

(3 x + 2)^{2} + 64 = 0

\frac{1 + \frac{x}{y}}{\frac{x}{y}}

- x^{2} + 4 x = 0

6 p^{2} - 5 p - 11 = 5 p^{2}

x x^{\frac{1}{2}}